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Recognizing Treelike k-Dissimilarities

机译:认识到Treelike k-Dissimilarities

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摘要

A k-dissimilarity D on a finite set X, |X| >= k, is a map from the set ofsize k subsets of X to the real numbers. Such maps naturally arise fromedge-weighted trees T with leaf-set X: Given a subset Y of X of size k, D(Y) isdefined to be the total length of the smallest subtree of T with leaf-set Y .In case k = 2, it is well-known that 2-dissimilarities arising in this way canbe characterized by the so-called "4-point condition". However, in case k > 2Pachter and Speyer recently posed the following question: Given an arbitraryk-dissimilarity, how do we test whether this map comes from a tree? In thispaper, we provide an answer to this question, showing that for k >= 3 ak-dissimilarity on a set X arises from a tree if and only if its restriction toevery 2k-element subset of X arises from some tree, and that 2k is the leastpossible subset size to ensure that this is the case. As a corollary, we showthat there exists a polynomial-time algorithm to determine when ak-dissimilarity arises from a tree. We also give a 6-point condition fordetermining when a 3-dissimilarity arises from a tree, that is similar to theaforementioned 4-point condition.
机译:有限集X | | X |上的k相异性D > = k是从X的大小为k的子集到实数的映射。这样的图自然来自具有叶子集X的边缘加权树T:给定X的大小为k的X的子集Y,D(Y)定义为具有叶子集Y的T的最小子树的总长度。 = 2,众所周知,可以通过所谓的“ 4点条件”来表征以这种方式产生的2个不同点。但是,在k> 2的情况下,Pachter和Speyer最近提出了以下问题:给定任意k的相似性,我们如何测试该图是否来自树?在本文中,我们提供了对此问题的答案,表明对于k> = 3 ak的相似性,集合X上的树是当且仅当它对X的每个2k元素子集的限制来自某个树,并且2k是最小的子集大小,以确保是这种情况。作为推论,我们证明了存在一种多项式时间算法来确定何时从树中产生ak不相似性。我们还给出了一个6点条件,用于确定何时从树中产生3个相异点,这与上述4点条件类似。

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